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Pure water is saturated with pure solid AgCl, a silver electrode is placed in the solution and the potential is measured agains normal calomet electrode at `25^(@)C`. This experiment is then repeated with a saturated solution of AgI. If the difference in potential in the two cases is 0.177V. What is the ratio of solubility product (solubility) of AgCl and AgI at the temperature of the experiment?

A

`10^(3)`

B

`10^(6)`

C

`10^(2)`

D

`10^(4)`

Text Solution

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The correct Answer is:
A
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