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The emf of a cell corresponding to the f...

The emf of a cell corresponding to the following reaction is 0.0199 V at 298 K.
`Zn(s) + 2H^(+)(aq) rightarrow Zn^(2+)(0.1M) + H_(2)(g)(E_(Zn//Zn^(2+))^(@) = 0.76V`
The approximate pH of the solution at the electrode where hydrogen is being produced is `[pH_(2) = 1 atm]`:

A

8

B

9

C

10

D

11

Text Solution

Verified by Experts

The correct Answer is:
C
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