Home
Class 12
CHEMISTRY
For which of these oxidation/reduction p...

For which of these oxidation/reduction pairs will the reduction potential vary with pH?
(P) `AmO_(2)^(2+) | Am^(4+)`
(R ) `Am^(4+) | Am^(2+)`

A

P only

B

Q only

C

P and Q only

D

P,Q and R

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTY

    GRB PUBLICATION|Exercise Batteries|10 Videos
  • ELECTROCHEMISTY

    GRB PUBLICATION|Exercise Thermodynamics in Electrochemistry|22 Videos
  • ELECTROCHEMISTY

    GRB PUBLICATION|Exercise Galvanic Cell and Salt Bridge|85 Videos
  • D-BLOCK ELEMENTS

    GRB PUBLICATION|Exercise Subjective Type|18 Videos
  • ENVIRONMENTAL CHEMISTRY

    GRB PUBLICATION|Exercise Straight objective type|40 Videos

Similar Questions

Explore conceptually related problems

For which of these oxidation/reduction pairs will the reduction potential vary with pH? I AmO_(2)^(2+)//AmO_(2)^(+) II. AmO_(2)^(2+)//Am^(4+) III Am^(4+) // Am^(2+)

In which of the following redox pairs, the reduction potential very, with pH ?

AM of 2 terms

Find the equation of the normal at the point (am^(2),am^(3)) for the curve ay^(2)=x^(3)

Find the equation of the normal at the point (am^(2),am^(3)) for the curve ay^(2)=x^(3)

Use the given standard reduction potentials to determine the reduction potential for this half-reactions. MnO_(4)^(-)(aq) + 3e^(-) + 4H^(+) rightarrow MnO_(2)(S) + 2H_(2)O(l)

Find the equation of the normal to the curve ay^(2)=x^(3) at the point (am^(2), am^(3)) .

Find the equation of tangent to the curve ay^(2)=x^(3) at the point (am^(2),am^(3))

Consider the following relations for (i) EMF of the cell =(Oxidation potential of anode) -(Reduction potential of cathode) (iii) EMF of the cell=(Reduction potential of anode) + (Reduction potential of cathode) (iv) EMF of the cell=(Oxidation potential of the anode)-(Oxidation potential of the cathode) which of the following above reactions are correct?

GRB PUBLICATION-ELECTROCHEMISTY-Latimer Diagram, concentration cells
  1. The emf of a cell corresponding to the following reaction is 0.0199 V ...

    Text Solution

    |

  2. Ni(s) + Cu^(2+)(aq) rightarrow Ni^(2+)(aq) + Cu(s) The voltaic cell ...

    Text Solution

    |

  3. For which of these oxidation/reduction pairs will the reduction potent...

    Text Solution

    |

  4. A variable, opposite external potential(E(ext) is applied to the ce...

    Text Solution

    |

  5. For the galvanic cell: Ag(s) | AgBr(aq) | Br^(-)(aq) || Cl^(-)(aq)| ...

    Text Solution

    |

  6. At 298 K, the standard reduction potential are: 1.33 V for Cr(2)O(7)^(...

    Text Solution

    |

  7. Which of the given cells are concentration cells? (P) Pt|H(2)(p(1)ba...

    Text Solution

    |

  8. In given galvanic cell, Pt|H-(2)(g) | NaCl(aq)|| AgNO(3)(aq)| Ag o...

    Text Solution

    |

  9. At 298 K, the standard reduction potentials are 1.51 V for MnO(4)^(-) ...

    Text Solution

    |

  10. Latimer diagram for Cu in an acidic solution is: Cu^(+2) overset(+0....

    Text Solution

    |

  11. The reduction of O(2) to H(2)O in acidic solution has a standard reduc...

    Text Solution

    |

  12. Pt(s), H(2)(g) |HCl(C(1))||HCl(C(2)|H(2),Pt(s) The emf of cell is at...

    Text Solution

    |

  13. Given the two standard reduction potentials below, what is the K(sp) o...

    Text Solution

    |

  14. An increase in pH will promote which of the reactions below? (P) 2Mn...

    Text Solution

    |

  15. Cu^(2+)(aq) + Zn(s) rightarrow Cu(s) + Zn^(2+)(aq), E^(@) = 1.1V Zn^...

    Text Solution

    |

  16. The EMF of the following cell: Zn| Zn^(2+)(0.1M) || Cl^(-)(0.01M) | ...

    Text Solution

    |

  17. The standard reduction potential of Cd^(2+)(aq) is -0.402V. A voltai...

    Text Solution

    |

  18. The cell potential for the voltaic cell depicted (according to IUPAC) ...

    Text Solution

    |

  19. A standard voltaic cell is constructed using Cu metal in 1.0 M Cu(NO(3...

    Text Solution

    |

  20. MnO(4)^(-) + 5Fe^(2+) + 8H^(+) rightarrow Mn^(2+) + 5Fe^(3=) + 4H(2)O ...

    Text Solution

    |