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Cu^(2+)(aq) + Zn(s) rightarrow Cu(s) + Z...

`Cu^(2+)(aq) + Zn(s) rightarrow Cu(s) + Zn^(2+)(aq)`, `E^(@) = 1.1V`
`Zn^(2+)(aq) + 2e^(-) rightarrow Zn(s),` `E^(@) = -0.76V`
`Cu^(2+)(aq) + 4NH_(3)(aq) rightarrow [Cu(NH_(3))_(4)]^(2+)(aq) + 2e^(-)` is:

A

0.34 V

B

0.76 V

C

0.26 V

D

0.14 V

Text Solution

Verified by Experts

The correct Answer is:
C
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Given the standard reduction potentials, which statement is correct? {:(Cu^(2)(aq) + 2e^(-) rightarrow Cu(s), E^(@) = 0.34V), (2H^(+)(aq) + 2e^(-) rightarrow H_(2)(g), E^(@)= 0.0V), (Cr^(3+)(aq) + 2e^(-) rightarrow Cr(s),E^(@) = -0.73V):}

Given these standard reduction potentials, what is the standard reduction potential for Co^(3+)(aq) + 3e^(-) rightarrow Co(s) ? Co^(3+)(aq) + e^(-) rightarrow Co^(2+)(aq) E^(@) = 1.82V Co^(2+)(aq) + 2e^(-) rightarrow Co(s) E^(@) = -0.28V

Use the information in the table and calcualate E^(@) for this reaction. Ga(s) + 3Tl^(+)(aq) rightarrow 3Tl(s) + Ga^(3+) (aq) {: ("Reaction", E^(@)), (Ga^(3+)(aq) + 3e^(-) rightarrow Ga(s), -0.529V), (Tl^(+)(aq) + e^(-) rightarrow Tl(s), -0.336V):}

Sn^(4+)(aq) + 2e^(-) rightarrow Sn^(2+)(aq) E^(@) = 0.15V Cr^(3+)(aq) + e^(-) rightarrow Cr^(2+)(aq) E^(@) = 0.41V According to the standard reduction potentials above, what is the value of E^(@) for the reaction below? 2Cr^(3+)(aq) + Sn^(2+)(aq) rightarrow 2Cr^(2+)(aq) + Sn^(4+)(aq)

Standard reduction potential of the half cell reactions are given below Co^(3+)(aq) + e^(1-) to Co^(2+)(aq) , E^0 = +1.81 V Au^(3+)(aq) + 3e^(1-) to Au(s) , E^0 = +1.40 V I_(2)(s) + 2e^(1-) to 2l^(1-)(aq) , E^0 = +0.54 V Cu^(2+)(aq) + 2e^(1-) to Cu(s) , E^0 = +0.34 V

A button cell used in watched funcations as follwing Zn(s)+Ag_(2)O(s)+H_(2)O(l)hArr2Ag(s)+Zn^(2+)(aq.)+2OH^(-)(aq) If half cell potentials are Zn^(2+)(aq.)+2e^(-) rarr Zn(s), E^(@) = -0.76 V Ag_(2)O(s)+H_(2)O(l)+2e^(-) rarr 2Ag(s)+2OH^(-)(aq.),, E^(@) = 0.34V The cell potential will be

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