Home
Class 12
PHYSICS
Two particles A(1) and A(2) of masses m(...

Two particles `A_(1) and A_(2)` of masses `m_(1), m_(2) (m_(1)gtm_(2))` have the same de-broglie wavelength. Then

A

their momenta ar the same

B

their energies are the same

C

energy of `A_(1)` is less than the energy of `A_(2)`

D

energy of `A_(1)` is more than the energy of `A_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A, C
Promotional Banner

Topper's Solved these Questions

  • ELECTRON,PHONTS,PHOTOELECTRIC EFFECT & X-RAYS

    CENGAGE PHYSICS|Exercise multiple correct|1 Videos

  • ELECTRON,PHONTS,PHOTOELECTRIC EFFECT & X-RAYS

    CENGAGE PHYSICS|Exercise dpp 3.2|15 Videos

  • ELECTRON,PHONTS,PHOTOELECTRIC EFFECT & X-RAYS

    CENGAGE PHYSICS|Exercise dpp 3.3|15 Videos

  • ELECTROMAGNETIC INDUCTION

    CENGAGE PHYSICS|Exercise compression type|7 Videos

  • Electrostatic Potential and Capacitance

    CENGAGE PHYSICS|Exercise QUESTION BANK|23 Videos

Similar Questions

Explore conceptually related problems

Two particles A_1 and B_2 of masses m_1 and m_2 (m_1 gt m_2) have the same de Broglie wavelength . Then

A particle of mass M at rest decay's into two particle of masses m_(1) and m_(2) having non zero velocity. The ratio of the de Broglie wavelengths of the masses lambda _(1) // lambda_(2) is

Assertion: A particle of mass M at rest decays into two particles of masses m_(1) and m_(2) , having non-zero velocities will have ratio of the de-broglie wavelength unity. Reason: Here we cannot apply conservation of linear momentum.

After absorbing a slowly moving neutrons of mass m_(N) (momentum ~0) a nucleus of mass M breaks into two nuclie of mass m_(1) and 5m_(1)(6m_(1)=M+m_(N)) , respectively . If the de-Broglie wavelength of the nucleus with mass m_(1) is lambda , then de Broglie wavelength of the other nucleus will be

A partical of mass M at rest decays into two Particles of masses m_1 and m_2 having non-zero velocities. The ratio of the de - Broglie wavelengths of the particles lambda_1| lambda_2 is (a) m_1//m_2 (b) m_2// m_1 (c ) 1 (d) sqrt,_2 // sqrt_1

A praticle of mass M at rest decays into two particle of masses m_1 and m_2 , having non-zero velocities. The ratio of the de Broglie wavelength of the particles (lamda_1)/(lamda_2) is

A particle of a mass M at rest decays into two particles of masses m_1 and m_2 having non-zero velocities. What is the ratio of the de-Broglie wavelength of the two particles?