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ABC is a very small equilateral triangle...

ABC is a very small equilateral triangles of side `0.5 xx 10^(-3)` m . A charge of `+20` aC (attocoulomb) is placed at the corner A and two charges , each of `-10`aC , at B and C . Calculate the potential at a point on the prolongation of AC 2 cm away from A .
[Hint: 1 aC (attocoulomb = `10^(-18)` coulomb]

Text Solution

Verified by Experts

The correct Answer is:
`1. 687 xx 10^(-7) V`
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Knowledge Check

  • The potential at a point due to charge of 5xx10^(-7)C located 10 cm away is

    A
    `3.5xx10^(5)V`
    B
    `3.5xx10^(4)V`
    C
    `4.5xx10^(4)V`
    D
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  • Charge of 5 mu C each are placed at the corners of an equilateral triangle of side 10 cm. Then the force on each charge is :-

    A
    78 N
    B
    39 N
    C
    29 N
    D
    22.5 N

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