Show that the potential at a point of coordinates (x,y) with reference to the axis of the dipole as x -axis and the line perpendicular to the axis and passing through the centre of the dipole as y-axis is
`V = (1)/(4piepsi_(0)) , (px)/((x^(2) + y^(2))^(3//2))` and hence show that the components of the field along x- and y- axis are given by ,
`E_(x) = (q)/(4pi epsi_(0)) , (2 x^(2) - y^(2))/((x^(2) + y^(2))^(5//2))`
`E_(y) = (p)/(4 pi epsi_(0)) , (3xy)/((x^(2) + y^(2))^(5//2))`
[Hint : Find the value of cos `theta` and r in terms of x and y and substitute their values in the standard formula `E_(x) = -(delV)/(delx) "and" E_(y) = -(delV)/(dely)`]