Home
Class 12
PHYSICS
A very short magnet is placed at a point...

A very short magnet is placed at a point O with its axis horizontal and perpendicular to the magnetic meridian. If P is a neutral point, show that tha angle between OP and the axis (SN direction) of the magnet is `tan^(-1)sqrt(2)`.

Promotional Banner

Topper's Solved these Questions

  • MAGNETIC DIPOLE

    NN GHOSH|Exercise EXERCISES|10 Videos
  • INTRODUCTORY NOTES

    NN GHOSH|Exercise Exercise|27 Videos
  • MAGNETIC EFFECT OF CURRENT

    NN GHOSH|Exercise Exercises|25 Videos

Similar Questions

Explore conceptually related problems

A short bar magnet is placed horizontally in N-S direction,with its north pole pointing to the north of earth.In this case,the neutral point is obtained

Show that the magnetic field at a point due to a magnetic dipole is perpendicular to the magnetic axis if the line joining the point with the centre of the dipole makes an angle of tan^(-1) (sqrt(2)) with the magnetic axis.

A magnetic needle free to rotate in a horizontal plane is placed at the centre of a circular current-carrying coil whose axis is perpendicular to the magnetic meridian at that place. It is also known that the magnetic declination at this place is zero and in this condition, the magnetic needle is pointing towards conditions, the magnetic needle is pointing towards the north-west. Now, if we reverse the direction of current in the coil, then the magnetic needle will

The direction of magnetic induction at a point on the axis of short magnetic dipole is

The magnetic potential at a point along the axis of a short magnetic dipole is

A short bar magnet is placed in a horizontal plane with its axis in the magnetic merdian . Null points are found on its equitorial line (i.e., its normal bisector) at 12.5 G and the angle of dip is zero. (i) What is the total magnetic field at points on the axis of the magnet located by the same distance (12.5 cm) as the null-points from the centre? (ii) Locate the null points when the magnet is turned around by 180^(@) . Assume that the length of the magnet is negligible as compared to the distance of the null-point from the centre of the magnet.

The dip at a place is delta. For measuring it, the axis of the dip needle is perpendicular to the magnetic meridian. If the axis of the dip needle makes angle theta with the magnetic meridian, the apparent dip will be given tan delta_(1) which is equal to:

The magnetic induction at a point on axis of a short magnetic dipole is