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A very short magnet is placed at a point...

A very short magnet is placed at a point O with its axis horizontal and perpendicular to the magnetic meridian. If P is a neutral point, show that tha angle between OP and the axis (SN direction) of the magnet is `tan^(-1)sqrt(2)`.

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Knowledge Check

  • A short bar magnet is placed horizontally in N-S direction,with its north pole pointing to the north of earth.In this case,the neutral point is obtained

    A
    `B_(eq)=B_(H)`
    B
    `B_(eq)=B_("axis")`
    C
    `B_(eq)=B_(V)`
    D
    `B_(eq)=2B_(H)`
  • A magnetic needle free to rotate in a horizontal plane is placed at the centre of a circular current-carrying coil whose axis is perpendicular to the magnetic meridian at that place. It is also known that the magnetic declination at this place is zero and in this condition, the magnetic needle is pointing towards conditions, the magnetic needle is pointing towards the north-west. Now, if we reverse the direction of current in the coil, then the magnetic needle will

    A
    point north - west
    B
    point north-east
    C
    point south-east
    D
    point south-west
  • The direction of magnetic induction at a point on the axis of short magnetic dipole is

    A
    In the direction of magnetic moment
    B
    Opposite to direction of magnetic moment
    C
    Perpendicular to direction of magnetic moment
    D
    Can not be predicted
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