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Find the locus of the points where the i...

Find the locus of the points where the intensity of the magnetic field due to a magnetic dipole will be perpendicular to its axis.

Text Solution

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The correct Answer is:
At `54^(@)42'` with the axis of the dipole
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Find the locus of points where the electric field due to a dipole is (i) perpendicular to its axis , (ii) anti-parallel to the axis . [Hint : "tan" alpha = ("tan"theta)/(2) ]

There is one short electric dipole placed on a horizontal plane. A circle is drawn assuming centre of dipole as centre of circle and plane of the circle is perpendicular to the axis of electric dipole. Thế number of points on this circle where electric field intensity due to electric dipole is perpendicular to the axis of dipole.

Knowledge Check

  • The magnetic induction at any point due to a short magnetic dipole is

    A
    `(pi_(0))/(4pi)(M)/(r^(3))sqrt(3cos^(2)theta+1)`
    B
    `(pi_(0))/(4pi) (2M)/(r^(2))sqrt(3cos^(2)theta+1)`
    C
    `(pi_(0))/(4pi)sqrt(3cos^(2)theta+1)`
    D
    `(pi_(0))/(4pi)(2M)/(r^(3)sqrt(3cos^(2)theta+1))`
  • Consider the situation of the previous problem. The directions of the magnetic field due to the dipole are opposite at

    A
    a tangent galvanometer
    B
    a diflection galvanometer if the earth's horizontal field is known
    C
    an oscillation magnetometer if the earth's horizontal field is known
    D
    both diflection and oscillation magnetometer if the earth's horizontal field is not known.
  • Intensity of magnetic field due to earth at a point inside a hollow steel box is

    A
    Less than outside
    B
    More than outside
    C
    same
    D
    Zero
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