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The earth may be considered to be a big ...

The earth may be considered to be a big dipole of moment `6.4 xx 10^(12)Am` placed at its centre with its axis in the SN direction. The radius of the earth is 6000 km. Calculate the horizontal and vertical components of the earth's magnetic field at a place whose lattitude is `22^(@)N`.
[Hint: `B_(r) = (mu_(0))/(4pi) (2m cos theta)/(r^(3))` and `B_(theta) = (mu_(0))/(4pi)(m sin theta)/(r^(3))`, here `theta = 90^(@) +22^(@) = 112^(@)`]

Text Solution

Verified by Experts

The correct Answer is:
`B_(v) = 2.22 xx 10^(-6)T` (downward), `B_(0) = 2.75 xx 10^(-6)T`
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