In a horizontal oil pipeline of constant cross-sectional area the pressure decrease between two point 300 km apart is 5000 pascal (1 pascal = 1 newton per square meter). What is the loss of energy per unit volume per unit distance?
[Hint : Loss in energy `=(P_(1))/(rho)-(P_(2))/(rho)` because `(P)/(rho)` is pressure energy per unit mass and loss in energy per unti volume `=P_(1)-P_(2)`.]

Answer

`0.01667`J