Home
Class 11
PHYSICS
Calculate the acceleration due to gra...

Calculate the acceleration due to gravity on the earth 's surface , given that gravitational constant `G = 6.7 xx 10^(-11)` SL unit , radius of he earth = ` 6. 4 xx 10 ^(6) m ` and mean density of earth = ` 5.5 xx 10^(3) kg m^(-3)`.

Text Solution

Verified by Experts

The correct Answer is:
`9.98 ms^(-2)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVITATION

    NN GHOSH|Exercise EXERCISE|29 Videos

  • FRICTION, WORK POWER AND ENERGY

    NN GHOSH|Exercise Exercises (B)|36 Videos

  • HYDRODYNAMICS

    NN GHOSH|Exercise EXERCISES|19 Videos

Similar Questions

Explore conceptually related problems

Calculate the mass and density of the earth. Given that Gravitational constant G = 6.67 xx 10^(-11) Nm^(2)// kg^(2) , the radius of the earth = 6.37 xx 10^(6) m and g = 9.8 m//s^(2) .

Calculate the acceleration due to gravity on the earth from the following data G= 6.6 xx 10 ^(-11) N m^(2) Kgm^(-3) Mean density of the earth = 5xx 10 ^(-3) kgm Radius of the earth = 6.4 xx10 ^(6) m .

Knowledge Check

  • Determine the gravitational potential on the surface of earth, given that radius of the earth is 6.4 xx 10^(6) m : its mean density is 5.5 xx 10^(3)kg m^(-3) , G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

    A
    `-6.297 xx 10^(7) J kg^(-1)`
    B
    `3.11 xx 10^(11) J kg^(-1)`
    C
    `4 xx 10^(8) J kg^(-1)`
    D
    `-2 xx 10^(9) J kg^(-1)`

    • Similar Questions

    Explore conceptually related problems

    Calculate the value of acceleration due to gravity at a place of latitude 45^(@) . Radius of the earth = 6.38 xx 10^(3) km .

    Find the magnitude of the acceleration due to gravity at the surface of the earth. ( M = 6 xx 10^(24) Kg, R = 6400 Km)

    Is the acceleration due to gravity of earth g a constant ? Discuss. Calculate the acceleration due to gravity on the surface of a satellite having a mass of 7.4 xx 10 ^(22) and a radius of 7.4 xx 10 ^(22) kg and a radius of 1.74 xx 10^(6)m G(=6.7 xx 10 ^(11) Nm^(2)//kg ^(2) ).Which satellite do you think it could be ?

    Calculate the speed of projection necessary to send a body right out of the filed of the earth's grvivtational attraction. G= 6.63 xx10^(-11) "newton metre^(2) " Kg^(2) Mass of the earth = 5.97 xx 10^(24) Radius of the earth = 6.37 xx 10^(6) m .

    A mango of mass 0.3 kg falls from a tree. Calculate the acceleration of the mango towards the earth. Also calculate the acceleration of the earth towards the mango. Take, Mass of the earth = 5.983 xx 10^(24) kg Radius of the earth = 6.378 xx 10^(6) m G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)

    How far away from the earth does the acceleration due to gravity become 10% of its value on earth's surface? Radius of earth = 6.37 xx 10^(6) m .

    An apple of mass 0.25 kg falls from a tree . What is the acceleration of the apple towards the earth ? Also calculate the acceleration of the earth towards the apple . Mass of the earth = 5.983 xx 10^(24) kg , Radius of the earth = 6.378 xx 10^(6) m and G = 6.67 xx 10^(-11)Nm^(2) kg^(-2)

    Home
    Profile