A car starts moving along a line, first with acceleration a=5 `ms^(-2)` starting from rest then uniformly and finally decelerating at the same rate a, comes to rest.The total time of motion is `tau=25 s`. The average velocity during the time is equal to lt v gt =72 km/hr.How long does the partial move uniformly ?

A car start moving along a line, fisrt with acceleration a=5 ms^-2 starting from rest then uniformly and finally decelerating at the same rate a, comes to rest. The total time of motion is pi=25s. The average velocity during the time is equal to lt v gt =72 km/hr . How long does the particle move uniformly ?

A car starts moving along a line, first with acceleration a=5m//s^(2) starting from rest then uniformly and finally decelerating at the same rate till it comes to rest. The total of motion is 25s . The average speed during the time is 20m//s . The particle moves uniformly for (2.5x) second. Find the value of x .

A car starts moving rectilinearly first with acceleration alpha=5 m s^(-2) (the initial velocity is equal to zero), then uniformly, and finally, deceleration at the same rate alpha comea to a stop. The time of motion equals t=25 s . The average velocity during this time is equal to =72 km h^(-1) How long does the car move unitromly?

A car accelerates from rest at a constant rate for some time after which it decelerates at a constant rate beta to come to rest. If the total time elapsed is t, the maximum velocity acquired by the car is given by :

A car,starting from rest, accelerates at the rate f through a distance s, then continuous at constant speed for time t and then decelerates at the rate f/2 come to rest. If the total distance traversed is 5 s,then :

A particle is moving under constant acceleration a=k t . The motion starts from rest. The velocity and displacement as a function of time t is

A car starts from rest and moves with uniform acceleration for time t then it moves with uniform speed of 60 km/h for time 3t and comes to rest. Find the average speed of car in its total journey.