Two identical buggies move one after the other due to inertia (without friction) with the same velocity `v_0`. A man of mass m rides the rear buggy. At a certain moment the man jumps into the front buggy with a velocity u relative to his buggy. Knowing that the mass of each buggy is equal to M, find the velocities with which the buggies will move after that.

Answer

`v_(1)=v_(0)+(mMv)/(M+m)^(2),v_(2)=v_(0)_(Mv)/(M+m)`