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A mass M attached to the end of a small flexible rope of diameter d=1 cm is raised vertically by winding the rope on a reel. If the reel is turned uniformly ay the rate of n=2 rps, what will be the tension T in the rope? Neglect inertia of the rope and slight lateral motion of the suspended mass. (Fig.5.25)

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The correct Answer is:
`T=Mg(1+(2pin^(2)d)/(g))=1.025 Mg`
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