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A circular section of radius r si cut ou...

A circular section of radius r si cut out of a uniform disc of radius R, the centre of the hole being R/2 from the centre of the original disc. Locate the centre of gravity of the remainder.

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The correct Answer is:
At a distance `(Rr^(2))/(2(R^(2)-r^(2)))` from the centre of the disc
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