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The handle of a floor mop makes an angle...

The handle of a floor mop makes an angle `theta ` with the vertical. If `mu_(k) and mu_(s)` be the coefficients of kinetic and static friction between floor and mop, show that if `theta` is smaller than certain value `theta_(0)`, the mop cannot be made to slide over across the floor, no matter how great a force is directed along the handle towards the centre. What is the angle `theta_(0)` ?

Text Solution

Verified by Experts

The correct Answer is:
`theta_(0)=tan^(-1) mu_(s)`
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