A weight of mass `m=1` kg attached to a spring of force constant `k = 20 N m"^(-1)` is able to oscillate on a rouch `(mu = 0.05)` steel rod. The displacement from the initial position of equilibrium is `a=30` cm. Find how many swings (i.e., movement from maximum to the equilibrium or back) will it make before coming to rest ? Take `g = 10 ms^(-2)`
[Hint : Use energy conservation to find `a_(n)` and hence have number of swings]

Answer

`N=(ka)/(mumg)-1=11`