calculate the angular momentum of a projectile of mass m at time t after its projection in a vertical plane with velocity v at angle `alpha` with the horizontal.

Two particles are simultaneously projected in the same vertical plane from the same point with velocities u and v at angles alpha and beta with horizontal. Find the time that elapses when their velocities are parallel.

A projectile si thrown with velocity of 50m//s towards an inclined plane from ground such that is strikes the inclined plane perpendiclularly. The angle of projection of the projectile is 53^(@) with the horizontal and the inclined plane is inclined at an angle of 45^(@) to the horizonta.. (a) Find the time of flight. (b) Find the distance between the point of projection and the foot of inclined plane.

The velocity at the maximum height of a projectile is half of its velocity of projection u . Its range on the horizontal plane is

An inclined plane making an angle beta with horizontal. A projectile projected from the bottom of the plane with a speed u at angle alpha with horizontal, then its maximum range R_("max") is

A particle of mass m is projected with a velocity v making an angle of 45^@ with the horizontal. The magnitude of the angular momentum of the projectile abut the point of projection when the particle is at its maximum height h is.

A projectile is projected with a speed of 40m/s at a angle theta with horizontal such that tantheta=(3)/(4) . After 2 sec, the projectile is moving with speed v at an angle alpha with horizontal then, (g=10m//s^(2))

A particle of mass m has been thrown with intial speed u making angle theta with the horizontal ground. Find the angular momentum of the projectile about an axis perpendicular to the plane and passing through the point of projection when the projectile is (a) At the highest point (b) About to hit the ground