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The minimum intensity of audibility of ...

The minimum intensity of audibility of a source is `01^(-12) "watt"//m^(2)`. If the frequency of the note is 1000 Hz, calculate the amplitude of vibrations of air particles. Density of air `= 1.293 kg m^(-3)` and velocity of sound `=340 ms^(-1)`
`["Hint " a = sqrt((I)/(2pi^(2)n^(2)rhoC)) ]`

Text Solution

Verified by Experts

The correct Answer is:
`1.07 xx 10^(-11) m`
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