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An electron moving with a velocity 10^(8...

An electron moving with a velocity `10^(8) m//s` enters a magnetic field at an angle of `20^(@)` to the direction of the field. Calculate
(a) The value of magnetic induction so that the helical path radius will be 2m.
(b) The time required to execute one revolution of the helical path.
(c) The pitch o fhelical path followed by the electron.

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Verified by Experts

The correct Answer is:
[(a) `9.6 xx 10^(-5) T`; (b) `3.69 xx 10^(-7)s`; (c) 34.68m]
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