A circular of radius 0.157 m has turns. ...

A circular of radius 0.157 m has turns. It is placed such that its axis is in magnetic meridian. A dip needle is supported at the centre of the coil with its axis of rotation horizontal, and in the plane of the coil. The angle of dip is `30^(@)` when a current flows through the coil. The angle of dip becomes `60^(@)` on reversing the current. Find the current in the coil assuming that the magnetic field due to the coil is smaller than the horizontal component of earth's magnetic field, `H =3xx10^(-5) T`.

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The correct Answer is:

[0.75 A]

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