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A magnet is suspended at an angle 60^(0)...

A magnet is suspended at an angle `60^(0)` in an external magnetic field of `5xx10^(-4)T`. What is the work done by the magnetic field in bringing it in its direction? `["The magnetic moment"=20A-m^(2)]`

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The correct Answer is:
`[-5 xx 10^(-3)]`
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