A particle accelerated by a potential difference `V` flies through a uniform transverse magnetic field with induction B. The field occupies a region of space din thickness. Prove that the angle a through which the particle deviates from the initial direction of its motion is given by.
`alpha=sin^(-1)(dBsqrt((q)/(2 Vm)))`
where `m` is the mass of the particle.

A proton accelarted by a potential differnce V = 500 kV fieles through a unifrom transverse magnetic filed the induction B = 0.54 T . The field occupies a region of space d = 10 cm in thickness (Fig). Find the angle alpha through which the proton deviates from the initial direction of its motion.

An electron accelerated through a potential difference V passes through a uniform transverse magnetic field and experiences a force F. If the accelerating potential is increased to 2V, the electron in the same field will experience a force

A charged particle having mass m and charge q is acceleration by a potential difference V, it files through a uniform tranverse magnetic field b.The field occupies a region of space d.Find the time interval for which it remains inside the magnetic field (i) An alpha particle is acceleration by a potential difference of 10^(4) V. Find the change in tis direction of motiom if it enters normally in a region of thicknees 0.1 , having transverse magnetic induction of 0.1T(m_(aplha)=6.4xx10^(-27)kg) (ii) a 10 g bullet having a charge of 4muC is fired at a speed 270ms^(-1) in a horizontal direction,A vertical magnetic field as it travels through 100 m .Make appropriate approximations

When an electron is accelerated through a potential difference V , it experience a fromce F through as uniform transverse magnetic field. If the potential difference is increased to 2 V, the force experoenced by the electron in the same magnetic field is

An electron of mass 'm' is accelerated through a potential difference of V and then it enters a magnetic field of induction B . Normal to the lines of force. Then the radius of the circular path is

A charge q is accelerated through a potential difference V . It is then passed normally through a uniform magnetic field , where it moves in a circle of radius r . The potential difference required to move it in a circle of radius 2 r is

A charged particle of mass m and charge q is accelerated through a potential differences of V volts. It enters of uniform magnetic field B which is directed perpendicular to the direction of motion of the particle. The particle will move on a circular path of radius