A rod of mass m and length 2R can rotate about an axis passing through O invertical plane.A disc of mass m and radius `R//2` is hinged to the other end P ofthe rod and can freely rotate about P. When disc is at lowest point both rod and disc has angular velocity `omega`. If rod rotates by maximum angle`theta=60^(@)` with downward vertical, then `omega` interms of R and g will be(all hinges are smooth)

Options

A. `sqrt((9g)/(16R))`
B. `sqrt((3g)/(23R))`
C. `(1)/(3)sqrt((g)/(R))`
D. None of these

Answer

A