The wheel of radius R rolls with out slipping on horizontal rough surface, and its centre O has an horizontal acceleration in `a_(0)` forward direction. A point P on the wheel is a distancer `r` from O and angular position `theta` from horizontal. For the given values of `a_(0)` R and r, determine the angle `theta` for which point P has no acceleration in this position.

Options

A. `cos^(1).(r)/(R)`
B. `tan^(1).(r)/(R)`
C. `sin^(1).(r)/(R)`
D. `cos^(1).(r)/(2R)`

Answer

C