A uniform ring of mass m and radius R is in uniform pure rolling motion on a horizontal surface. The velocity of the centre of ring is `V_(0)`. The kinetic energy of the segment ABC is:

Options

A. `(mV_(0)^(2))/(2)-(mV_(0)^(2))/(pi)`
B. `(mv_(0)^(2))/(2)+(mv_(0)^(2))/(pi)`
C. `(mv_(0)^(2))/(2)`
D. `mv_(0)^(2)`

Answer

A