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A conical vessel wihout a bottom stands ...

A conical vessel wihout a bottom stands on a table. A liquid is poured with the vessel & as soon as the level reaches h, the pressure of the liquid raises the vessel. The radius of the base of the vessel is R and half angle of the cone `alpha` and the weight of the vessel is W. What is the density of the liquid ?

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The correct Answer is:
`[rho = (W)/(pi h^(2) rho g tan alpha(R-(1)/(3) h tan alpha))]`
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