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Gold has a specific heat of 130Jkg*""^(@...

Gold has a specific heat of 130Jkg`*""^(@)C` and wood has a specific heat of `1,800Jkg*""^(@)C`. If a piece of gold and a piece of wood, each of mass 0.1 kg, both absorbs 2.340 J of heat, by how much will their temperatures rise?

Text Solution

Verified by Experts

We're given c,m, and Q, and we know that `DeltaT=Q//(mc)`.
`DeltaT_("gold")=(Q)/(mc_("gold"))=(2.340J)/((0,1kg)(130J//kg*""^(@)C))=180^(@)`
`DeltaT_("wood")=(Q)/(mc_("wood"))=(2,340J)/((0,1kg)(1,800J//kg*""^(@)C))=13^(@)C`
Notice that the temperature of gold increased by `180^(@)C`, but the temperature of the wood increased by only `13^(@)C`.
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