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In a battery of 10 cell supposed to be i...

In a battery of 10 cell supposed to be in series some are wrongly connected. The cells are sealed in a box. When a similar cell is connected in opposition to the battery, the current produced by the combination through an external resistor of `14.5Omega` is 0.075 A. How many cells are wrongly connected? What is the emf of the battery and what is its internal resistance if emf of each cell is 1.5V and internal resistance `0.5Omega`?

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The correct Answer is:
4,3V, 5 `Omega`
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NN GHOSH-FUNDAMENTAL OF CURRENT ELECTRICITY-Exercises
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  2. Two batteries of emf epsilon(1) and epsilon(2) produce a current of 1....

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  3. In a battery of 10 cell supposed to be in series some are wrongly conn...

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  4. How you would arrange 24 cells, each of emf 1.5V and internal resistan...

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  8. Calcualte the resistance of a steel wire of length 10m and diameter 0....

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  9. Three wires whose lengths are in the ratio 3:8:18 and radii in the rat...

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  10. A moving coil galvanometer of resistance 50Omega is connected in serie...

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  11. A resistance box, a battery and a galvanometer of resistance G ohm are...

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  12. A shunt is to be applied to a galvanometer of 99Omega so that only 10%...

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  13. Two identical cells of emf 1.5V and internal resistance 1Omega are joi...

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  14. A battery of emf 6V internal resistance 5Omega is joined in parallel w...

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  15. A battery of emf 6 volts and internal resistance 1Omega is connected i...

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  16. Two batteries of emfs 24V and 6V and internal resistance 2Omega and 1O...

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  17. The sides of a square ABCD are formed of wires, each of resistance r a...

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  18. In a wheatstone bridge, the resistance of the arms of the bridge are A...

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  19. ABCD is a square of side a meters and is mae up of wires of resistance...

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  20. A battery of 2V and internal resistance 2Omega is used in wheatstone b...

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