A circular loop is placed in the magnetic meridian. Find the deflectioin it will produce in a compass it will produce in a compass needle placed 10cm from its center. H-vector of earth's field = 30Am^(-1)`. Radius of the loop = 10cm and number of turns = 10. Current through the loop = 0.5A

A circular loop is placed in magnetic field B=2t. Find the direction of induced current produced in the loop.

A circular coil with 10 turns of mean radius 10 cm is placed in the magnetic meridian. A current of 0.5 A is passed through the coil. What is the defelctioin of a compass needle placed at the center of the coil? If the coil is rotated, at wht angle will the needle placed to the plane of the coil? If the coil is rotated, at what angle will the needle set parallel to the plane of the coil?)H of earth's field = 30 Am^(-1)

A circular coil has 63 turns, each of radius 22cm. It is placed in the magnetic meridian. A current of 0.5A is passed through the coil. What is the deflectio of a compass needle placed at its center is 45^(@) . Calcualte the intensity of the earth's horizontal field.

A coil of 50 turns and radius 10 is placed with its plant at right angles to the magnetic meridian. It is connected to a cell of steady emf and a rheostat. The current through the coil is gradually increased till a compass needle at its center just turns through 180^(@) . Find the strength and direction of current through the coil. (Horizontally intensity of earth's field = 30 A m^(-1)

Calcualte the current in amperes through a circular loop of 40 turns and mean radius 5cm placed with its planein the magnetic meridian that will produce a deflection of 60^(@) in a compass needle placed at its center. (The value of horizontal induction = 3.5 xx 10^(-5)T)

A circular loop of 2 turns carries a current of 5*0A . If the magnetic field at the centre of loop is 0*40mT , find the radius of the loop.

A magnet whose poles are 12 cm apart is placed in the magnetic meridian. The field due to this magnet counterbalances the earth's horizontal field (H = 30 Am^(-1)) at a point 10 cm from each pole. Find the pole strength of the magnet.