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A body is projected with a velocity of 3...

A body is projected with a velocity of `30 ms^(-1)` at an angle of `30^(@)` with the vertical. Find the maximum height, time of flight and the horizontal range.

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A body is projected with a velocity 30 ms^(-1) at an angle of 30^@ with the vertical. Find (i) the maximum height (ii) time of flight and (iii) the horizontal range of the projectile. Take g=10 m//s^@ .

A particle is projected with a velocity of 25 m//s at an angle of 30^(@) with the horizontal . Calculate (i) The maximum height , (ii) time of flight and (iii) horizontal range .

Knowledge Check

  • A body of mass 1kg is projected with velocity 50 ms^(-1) at an angle of 30^(@) with the horizontal. At the highest point of its path a force 10 N starts acting on body for 5s vertically upward besids gravitational force, what is horizontal range of the body (Take, g = 10 ms^(-2))

    A
    `125 sqrt(3)`
    B
    `200 sqrt(3)m`
    C
    `500m`
    D
    `250 sqrt(3)m`
  • A body is projected with a velocity 60 ms ^(-1) at 30^(@) to horizontal . Its initial velocity vector is

    A
    `10 hati + 10 sqrt3 hatj `
    B
    ` 30 hati + 30 sqrt3 hatj`
    C
    `30sqrt(3hati) + 30 hatj`
    D
    `30sqrt(3hati)`
  • A stone projected with a velocity u at an angle theta with the horizontal reaches maximum height H_1 . When it is projected with velocity u at an angle (pi/2 - theta) with the horizontal, it reaches maximum height H_2 . The relation between the horizontal range R of the projectile, heights H_1 and H_2 is

    A
    `R= 4sqrt(H_1 H_2)`
    B
    `R= 4(H_1 - H_2)`
    C
    `R=4(H_1 + H_2)`
    D
    `R= (H_1^2)/(H_2^2)`
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