A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to `(-K//r^(2))`, where k is a constant. The total energy of the particle is -

A particle of mass m is moving is a horizontal circle of radius x under a centripetal force equal to - (kv^(2)) where it is constant The total energy of the particle is

A particle of mass m is moving in a horizontal circle of radius R under a centripetal force equal to -A/r^(2) (A = constant). The total energy of the particle is :- (Potential energy at very large distance is zero)

If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-1//r^(2)) , the total energy is

If a body of mass m is moving along a horizontalcircle of radius R, under the action of centripetal force equal to K//R^(2) where K is constant then the kinetic energy of the particle will be

A satellite of mass M is moving in a circle of radius R under a centripetal force given by (-K//R^(2)), where k is a constant. Then

IF a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-(K)/(r^(2))) , then its total energy is

A particle of mass m is moving in a circular path of constant radius r , such that its centripetal force F_r varies with time t as F_r=K^2rt^2 , where k is a constant. What is the power delivered to the particle by the forces acting on it?

A particle of mass m impves along a horzontal circle of radius R such that normal acceleration of particle varies with time as a_(n)=kt^(2). where k is a constant. Total force on particle at time t s is

A particle of mass m moves in a circular orbit under the central potential field, U(r)==-C/r, where C is a positive constant. The correct radius -velocity graph of the particle's motion is.

A particle of mass m impves along a horzontal circle of radius R such that normal acceleration of particle varies with time as a_(n)=kt^(2). where k is a constant. Tangential force on particle at t s is