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A sample of calcuium carbonate (CaCO(3))...

A sample of calcuium carbonate `(CaCO_(3))` has the following percentage composition: `Ca=40%, C=12%, O=48%` If the law of constant proportions is true. Then the weight of calcium in `4 g` of a sample of calcium carbonate obtained from another source will be

A

`0.016 g`

B

`0.16 g`

C

`1.6 g`

D

`16 g`

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