In the mixture of (NaHCO(3)+Na(2)CO(3)) ...

In the mixture of `(NaHCO_(3)+Na_(2)CO_(3))` volume of HCl required is x mL with phenolphthalein indicator and then y mL with methyl orange indicator in same titration Hence, volume of HCl for complete reaction of `Na_(2)CO_(3)` is

x/2

(y-x)

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In the mixture of NaHCO_(3) and Na_(2)CO_(3) , the volume of a given HCl required is x mL with phenolphthalein indicator and further y mL required with methyl orange indicator. Hence volume of HCl for complete reaction NaHCO_(3) is

A sample of NaHCO_(3) + Na_(2)CO_(3) required 20 ml of HCl using phenolphthalein as indicator and 35ml more required if methyl orange is used as indicator . Then molar ratio of NaHCO_(3) to Na_(2)CO_(3) is

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A mixutre solution of KOH and Na_2CO_3 requires 15 " mL of " (N)/(20) HCl when titrated with phenolphthalein as indicator.But the same amoound of the solutions when titrated with methyl orange as indicator requires 25 " mL of " the same acid. Calculate the amount of KOH and Na_2CO_3 present in the solution.

When Na_(2)CO_(3) solution is titrated against HCl solution, the indicator used is

A mixture NaOH+Na_(2)CO_(3) required 25mL of 0.1 M HCl using phenolpththalein as the indicator. However, the same amount of the mixture required 30mL of 0.1M HCl when methyl orange was used as the indicator. The molar ration of NaOH and Na_(2)CO_(3) in the mixture was:

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