Home
Class 11
CHEMISTRY
A mineral consists of an equimolar mixtu...

A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 12.5% by mass.2.8 g of the mineral on heating loat 1.32g of `CO_(2)`. What is the % by mass of the other metal ?

A

87.5

B

35.71

C

65.11

D

23.21

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY

    NARENDRA AWASTHI|Exercise Level 2 (Q.31 To Q.35)|5 Videos
  • STOICHIOMETRY

    NARENDRA AWASTHI|Exercise Level 3 - Passage|18 Videos
  • STOICHIOMETRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.181 To Q.200)|20 Videos
  • SOLID STATE

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos
  • THERMODYNAMICS

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|2 Videos

Similar Questions

Explore conceptually related problems

A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 12.5% by mass 2.8g of the mineral on heating lost 1.32g of CO_2 . What is the % by mass of the other metal ?

A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 15.0% by weight, 3.0 g of the mineral on heating lost 1.10 g of CO_(2) . The percent by weight of other metal is

A mixture contains equi-molar quantities of carbonates of two bivalent metals. One metal is present the extent of 13.5% by weight in the mixture and 2.50 g of the mixture on heating leaves a residue of 1.18 g . Calculate the percentage by weight of the other metal.

1.00 g of a mixture, consisting of equal number of moles of carbonates of two alkali metals, required 44.4 " mL of " 0.5 N-HCl for complete reaction. If the atomic weight of one of the metal is 7.00. Find the atomic weight of the other metal. What will be the total amount of sulphate formed on quantitative conversion of 1.00 g of the mixture into sulphates?

NARENDRA AWASTHI-STOICHIOMETRY-Level 2 (Q.1 To Q.30)
  1. Calculate the number of millilitre of NH3 (aq) solution (d=0.986 g/mL)...

    Text Solution

    |

  2. In the preparation of iron from haematite (Fe2O3) by the reduction wit...

    Text Solution

    |

  3. A mineral consists of an equimolar mixture of the carbonates of two bi...

    Text Solution

    |

  4. 6.2 g of a sample containing NaHCO(3), NaHCO(3) and non -volatiale in...

    Text Solution

    |

  5. Nitric acid canbe produced from NH(3)in three steps process given belo...

    Text Solution

    |

  6. 1 M NaOH solution was slowly added in to 1000 mL of 183.75 g impure H(...

    Text Solution

    |

  7. MnO(2) on ignition converts into Mn(3)O(4). A sample of pyrolusite hav...

    Text Solution

    |

  8. A 1.0g sample of a pure organic compound cotaining chlorine is fused w...

    Text Solution

    |

  9. A 0.6gm sample consisting of only CaC(2)O(4) and MgC(2)O(4) is heated ...

    Text Solution

    |

  10. A metal M forms the sulphate M(2)(SO(4))(3). A 0.596 gram sample of t...

    Text Solution

    |

  11. Urea(H(2)NCONH(2)) is manufactured by passing CO(2)(g) through ammonia...

    Text Solution

    |

  12. 11.6 g of an organic compound having formula (C(n)H(2n+2)) is burnt in...

    Text Solution

    |

  13. H(2)O(2)+2KIoverset(40% "yield")rarrI(2)+2KOH H(2)O(2)+2KMnO(4)+3H(2...

    Text Solution

    |

  14. SO(2)Cl(2) (sulphuryl chloride ) reacts with water to given a mixture ...

    Text Solution

    |

  15. 5 g sample contain only Na(2)CO(3) and Na(2)SO(4) . This sample is dis...

    Text Solution

    |

  16. 20 mL of 0.2 M NaOH(aq) solution is mixed with 35 mL of this 0.1 ML N...

    Text Solution

    |

  17. A silver coin weighing 11.34 g was dissolved in nitric acid When sodiu...

    Text Solution

    |

  18. Two elements A and B combine chemically to from compounds combinin...

    Text Solution

    |

  19. The conversion of oxygen to ozone occurs to the extent of 15% only. Th...

    Text Solution

    |

  20. RH(2) (ion exchange resin) can replace Ca^(2+) ions in hard water as R...

    Text Solution

    |