11.6 g of an organic compound having for...

11.6 g of an organic compound having formula `(C_(n)H_(2n+2))` is burnt in excess of `O_(2)(g)` initially taken in a 22.41 litre steel vessel. Reaction the gaseous mixture was at 273 K with pressure reading 2 atm. After complete complete combustion and loss of considerable amount of heat, the mixture of product and excess of `O_(2)` had a temperature of 546 K and 4.6 atm pressure. The formula of organic compound is :

`C_(6)H_(6)`

`C_(3)H_(8)`

`C_(5)H_(12)`

`C_(4)H_(14)`

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

STOICHIOMETRY
NARENDRA AWASTHI|Exercise Level 2 (Q.31 To Q.35)|5 Videos
STOICHIOMETRY
NARENDRA AWASTHI|Exercise Level 3 - Passage|18 Videos
STOICHIOMETRY
NARENDRA AWASTHI|Exercise Level 1 (Q.181 To Q.200)|20 Videos
SOLID STATE
NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos
THERMODYNAMICS
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|2 Videos

Similar Questions

Explore conceptually related problems

1 ml of gaseous aliphatic compound C_(n) H_(3n) O_(m) is completely burnt in an excess of O_(2) . The contraction in volume is

36 ml of a gaseous mixture consisting of a gaseous organic compound A and just sufficient amount of oxygen required for complete combustion gives 16 ml of CO_(2) , 24 ml water vapour and 8 ml of N_(2) . The volumes are measured at same temperature and pressure. The molecular formula of compound will be.

60 g of gaseous C_(2)H_(6) are mixed with 28 g of carbon monoxide. The pressure of the resulting gaseous mixture is 3 atm. The partial pressure in atm. Of C_(2)H_(6) in the mixture is

If a mixture of CO and N_(2) in equal amount have total 1 atm pressure, then partial pressure of N_(2) in the mixture is

28 g of N_2 at 299.6 K having a pressure of 2.46 atm Occupy

The total pressure of a gaseous mixture of 2.8 g N_(2) , 3.2 g O_(2) , and 0.5 g H_(2) is 4.5 atm . Calculate the partial pressure of each gas.

NARENDRA AWASTHI-STOICHIOMETRY-Level 2 (Q.1 To Q.30)

A 0.6gm sample consisting of only CaC(2)O(4) and MgC(2)O(4) is heated ...
Text Solution
|
A metal M forms the sulphate M(2)(SO(4))(3). A 0.596 gram sample of t...
Text Solution
|
Urea(H(2)NCONH(2)) is manufactured by passing CO(2)(g) through ammonia...
Text Solution
|
11.6 g of an organic compound having formula (C(n)H(2n+2)) is burnt in...
Text Solution
|
H(2)O(2)+2KIoverset(40% "yield")rarrI(2)+2KOH H(2)O(2)+2KMnO(4)+3H(2...
Text Solution
|
SO(2)Cl(2) (sulphuryl chloride ) reacts with water to given a mixture ...
Text Solution
|
5 g sample contain only Na(2)CO(3) and Na(2)SO(4) . This sample is dis...
Text Solution
|
20 mL of 0.2 M NaOH(aq) solution is mixed with 35 mL of this 0.1 ML N...
Text Solution
|
A silver coin weighing 11.34 g was dissolved in nitric acid When sodiu...
Text Solution
|
Two elements A and B combine chemically to from compounds combinin...
Text Solution
|
The conversion of oxygen to ozone occurs to the extent of 15% only. Th...
Text Solution
|
RH(2) (ion exchange resin) can replace Ca^(2+) ions in hard water as R...
Text Solution
|
100 cm^(3) of a solution of an acid (Molar mass =98) containing 29.4 g...
Text Solution
|
20 mL of 0.1 M solution of compound NaCO(3).NaHCO(3).2H(2)O is titrate...
Text Solution
|
A sample containing HAsO(2) (mol. Mass=108) and weighing 3.78 g is dis...
Text Solution
|
A mixture of FeO and Fe(2)O(3) is completely reacted with 100 mL of 0...
Text Solution
|
To a 10mL, 1M aqueous solution of Br(2), excess of NaOH is added so th...
Text Solution
|
0.10 g of a sample containing CuCO(3) and some inert impurity was diss...
Text Solution
|
1 mole of equimolar mixture of ferric oxalate and ferrous oxalate requ...
Text Solution
|
An impure sample of sodium oxalate (Na(2)C(2)O(4) weighing 0.20 g is d...
Text Solution
|