20 mL of 0.1 M solution of compound NaCO...

20 mL of 0.1 M solution of compound `NaCO_(3).NaHCO_(3).2H_(2)O` is titrated against 0.05 M HCL. X mL of HCL is used when phenolphthalein is used as an indicator and y mL of HCL is used when methly orange is the indicator in two separate titrations. Hence (y-x) is:

40 mL

80 mL

120 mL

None of these

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40 mL of 0.05 M solution of sodium sesquicarbonate (Na_(2)CO_(3).NaHCO_(3).2H_(2)O) is titrated against 0.05 M HCl.When phenoplhthalein is used as indicator, x mL HCl is used. In a separate titration of same using methyl orange as indicator, y ml of HCl is used . The value of (y-x) is :

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A sample of NaHCO_(3) + Na_(2)CO_(3) required 20 ml of HCl using phenolphthalein as indicator and 35ml more required if methyl orange is used as indicator . Then molar ratio of NaHCO_(3) to Na_(2)CO_(3) is

0.1g of a solution containing Na_(2)CO_(3) and NaHCO_(3) requires 10mL of 0.01 N HCl for neutralization using phenolphthalein as an indicator, mass% of Na_(2)CO_(3) in solution is:

NARENDRA AWASTHI-STOICHIOMETRY-Level 2 (Q.1 To Q.30)

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