Home
Class 11
CHEMISTRY
If 1 mole of H(3)PO(4) reacts with 1 mo...

If 1 mole of `H_(3)PO_(4)` reacts with 1 mole of `X(OH)_(2)` as shown below :
`H_(3)PO_(4)+X(OH)_(2) to XHPO_(4)+2H_(2)O " then"`

A

the equivalent mass of base is `(mol.mass)/(2)`

B

the eq. mass of `H_(3)PO_(4)` is `(98)/(3)`

C

the resulting solution requires 1 mole NaOH for complete neutralization

D

minimum 1 mole of X`(OH)_(2)` is required for complete neutralization of `XHPO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A, C
Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|5 Videos

  • STOICHIOMETRY

    NARENDRA AWASTHI|Exercise Level 3 - Assertion - Reason Type Questions|15 Videos

  • STOICHIOMETRY

    NARENDRA AWASTHI|Exercise Level 3 - Passage|18 Videos

  • SOLID STATE

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

  • THERMODYNAMICS

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|2 Videos

Similar Questions

Explore conceptually related problems

If 1 mole of H_(4)P_(2)O_(7) is reacted with 1 mole of A(OH)_(3) as H_(4)P_(2)O_(7)+A(OH)_(3) toAHP_(2)O_(7)+3H_(2)O then: (Atomic wt. of A=69,P=31)

Find the n factor of H_(3) PO_(4) in the following reaction. H_(3) PO_(4) + Ca(OH)_(2) rarr CaHPO_(4) + 2H_(2) O

H_(3)underline(P)O_(5)+H_(2)O to H_(3)PO_(4)+H_(2)O_(2)

H_(3)PO_(2)+CuSO_(4) to Cu darr+H_(3)PO_(4)+HNO_(3)

Statement-1 : 2 moles of BaCl_(2) react with 3 moles of Na_(3)PO_(4) to form 0.66 mole of Ba_(3)(PO_(4))_(2) Statement-2 : BaCl_(2) is the limiting reactant and some Na_(3)PO_(4) remains unreacted.

Calculate equivalent weight of H_(3)PO_(4) and Ca(OH)_(2) on the basis of given reaction. H_(3)PO_(4)+ NaOH to NaH_(2)PO_(4)+ H_(2)O Ca(OH)_(2)+ HCL to Ca(OH)CL+ H_(2)O

The Ew of H_(3) PO_(4) in reaction is Ca(OH)_(2) + H_(3) PO_(4) rarr CaHPO_(4) + 2H_(2)O (Ca = 40, P = 31, O = 16)