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The Schrodinger wave equation for hydrog...

The Schrodinger wave equation for hydrogen atom is `Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0))` , where `a_(0)` is Bohr's radius . If the radial node in 2s be at `r_(0)` , then `r_(0)` would be equal to :

A

`(a_(0))/(2)`

B

`2a_(0)`

C

`sqrt(2)a_(0)`

D

`(a_(0))/(sqrt(2))`

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NARENDRA AWASTHI-ATOMIC STUCTURE-Exercise
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  4. The Schrodinger wave equation for hydrogen atom is Psi("radial")=(1)...

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  11. The velocity of an e in excited state of H-atom is 1.093 xx 10^(6)m//s...

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  12. The angular momentum of an electron in a Bohr's orbit of He^(+) is 3.1...

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  13. If radiation corresponding to second line of "Balmer series" of Li^(+2...

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  20. For a 3s - orbital, value of Phi is given by following realation: Ps...

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