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An element undergoes a reaction as show...

An element undergoes a reaction as shown `sx+2e^(-)tox^(-2)`
Energy released `=30.87` ev/atom. If the energy released is used to dissociated `4g` to `H_(2)` molecules equally into `H^(+)` and `H^(+)` is excited state of `H` atoms where the electron travels in orbit whose circumference equal to four times its de -roglie's wavelength. Determine the minimum number of moles of `x` that would be required.
Given IE of `H=13.6` ev/atom, bond energy of `H_(2)=4.526`v/molecule

A

1

B

2

C

3

D

4

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An element undergoes s reaction as show - X+2e^(-) rarrX^(2-) , energy relesed =30.87eV//"atom" . If the energy released ,is used to dissociate 8 gms of H_(2) molecules,equally into H^(+) and H^(ast) ,where H^(ast) is an exicted state of H atoms where the electron travels in orbit whose circumference equal to four times its de Broglie's wavelenght . (a) Calculate the excited statue of H (b) Determine the least amount of X that would be required . Given : IE of H = 13.6 eV//"atom" , Bond energy of H_(2) =4.526 eV//"molecule" .

The de Broglie's wavelength of electron present in first Bohr orbit of 'H' atom is :

Energy of electron in a orbit of H -atom is

In H-atom electron jumps from 3^(rd) to 2^(nd) energy level, the energy released is -

The velocity of an e in excited state of H-atom is 1.093 xx 10^(6)m//s , what is the circumference of this orbit?

If the de-Broglie wavelength of an electron revolving in 2^"nd" orbit of H-atom is x, then radius of that orbit is given by :

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