For `3s` orbital of hydrogen atom, the normalised wave function is
`Psi_(3s)=(1)/((81)sqrt(3pi))((1)/(a_(o)))^(3//2)[27-(18r)/(a_(o))+(2r^(2))/(a_(o)^(2))]e^((-r)/(3a_(o)))`
If distance between the radial nodes is d, calculate rthe value of `(d)/(1.73a_(o))`

The wave function of 3s electron is given by Psi_(3s)=1/(81sqrt(3)prod)(1/a_(0))^(3//2)[27-18(r/a_(0))+2(r/a_(0))^(2)]e^(-r//3a_(0)) It has a node at r=r_(0) , Find out the relation between r_(0) and a_(0)

For the wave function Psi= (sqrt2)/(81sqrtpi a_(0)^(3//2))[6 - (r)/(a_(0))](r)/(a_(0)) xx e^(-r//3a_(0)) "sin"theta dot"cos"phi Identify the orbital .

The wave function of 2s electron is given by W_(2s) = (1)/(4sqrt(2pi))((1)/(a_(0)))^(3//2)(2 - (r )/(a_(0)))e^(-1 a0) It has a node at r = r_(p) .Find the radiation between r_(p) and a

[" The Schrodinger wave equation "],[" for hydrogen atom is: "],[qquad [psi_(2s)=(1)/(4sqrt(2 pi))((1)/(a_(0)))^(3/2)(2-(r_(0))/(a_(0)))e^((-r_(0))/(a_(0))),],[" where "a_(0)" is Bohr's radius.If the "],[" radial node is "2s" be at "r_(0)," then the "],[" value of "(r_(0))/(a_(0))" is "]]

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

Consider psi (wave function) of 2s atomic orbital of H-atom is- psi_(2s)=(1)/(4sqrt(2pia_(0)^(3//2)))[2-(r )/(a_(0))]e^.(r )/(2a_(0) Find distance of radial node from nucleous in terms of a_(0)