The degree of an electrolyte is a and its Van't Hoff factor is i. The number of ions obtained by complete dissociation of 1 molecules of electrolyte as :
A
`(i+a-1)/a`
B
i- a - 1
C
`(i-1)/a`
D
`i+1+a/(1-a)`
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The correct Answer is:
a
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DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 1 (Q.62 To Q.91)|1 Videos
The degree of dissociation of an electrolyte is alpha and its van't Hoff factor is i . The number of ions obtained by complete dissociation of 1 molecules of the electrolyte is :
If van't Hoff factor i=1,then
For a non-electrolytic solution, van't Hoff factor is equal to
van't Hoff factor (i) is given by the expression
, van't -Hoff factor (i) for this reaction is:
An electrolyte XY_(2) is 40% ionized. Calculate van't Hoff factor
For electrolytic solution, the Van't Hoff factor (i) is always equals to unity.
The degree of dissociation alpha of a week electrolyte is where n is the number of ions given by 1 mol of electrolyte.
Van't Hoff factor, i lt 1 if there is association of the solute in the solution.
NARENDRA AWASTHI-DILUTE SOLUTION-Level 3 - Match The Column
