Home
Class 11
CHEMISTRY
if the elevation in boiling point of a s...

if the elevation in boiling point of a solution of non-volatile, non-electrolytic and non-associating solute in solvent (`K_(b) =xK.kgt."mol"^(-1)`)is y K, then the depression in freezing point of solution of same concentration would be
(`K_(f)` )of the solvent = `zk.kg"mol"^(-1)`)

A

`2xy/y`

B

`yz/x`

C

`xz/y`

D

`yz/(2x)`

Text Solution

Verified by Experts

The correct Answer is:
b
Promotional Banner

Topper's Solved these Questions

  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 1 (Q.62 To Q.91)|1 Videos
  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 2|3 Videos
  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos
  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

Similar Questions

Explore conceptually related problems

Calculate depression in freezing point of 0.03 m solution of K_(2)SO_(4) (assumed ionised) in a solvent with K_(f)=4K kg "mol"^(-1)

The freezing point of a 0.05 molal solution of a non-electrolyte in water is: ( K_(f) = 1.86 "molality"^(-1) )

Elevation in boiling point of an aqueous solution of a non-electroluyte solute is 2.01^(@) . What is the depression in freezing point of the solution ? K_(b)(H_(2)O)=0.52^(@)mol^(-1)kg K_(f)(H_(2)O)=1.86^(@)mol^(-1)kg

What is the depression in freezing point of a solution of non-electrolyte if elevation in boiling point is 0.13K ? (k_(b)=0.52 mol^(-1) kg, k_(f)= 1.86 mol^(-1) kg)

The freezing point of a 0.05 molal solution of a non-electrolyte in water is [K_(f)=1.86K//m]

Elevation in boiling point of a solution of non-electrolyte in CCl_(4) is 0.60^(@)C . What is the depression in freezing point for the same solution? K_(f)(CCl_(4)) = 30.00 K kg mol^(-1), k_(b)(CCl_(4)) = 5.02 k kg mol^(-1)

Elevation in boiling point of a solution of non-electrolyte in CCl_(4) is 0.60^(@)C . What is the depression in freezing point for the same solution? K_(f)(CCl_(4)) = 30.00 K kg mol^(-1), k_(b)(CCl_(4)) = 5.02 k kg mol^(-1)