If 0.1 m aqueous solution of calcium phosphate is 80% dissociated then the freezing point of the solution will be ( K_f of water = 1.86K kg mol^(-1))
A 0.2 molal aqueous solution of a weak acid HX is 20% ionized. The freezing point of the solution is (k_(f) = 1.86 K kg "mole"^(-1) for water):
In a 2.0 molal aqueus solution of a weak acid HX the degree of disssociation is 0.25. The freezing point of the solution will be nearest to: ( K_(f)=1.86 K kg "mol"^(-1) )
A 0.2 molar aqueous solution of a weak acid (HX) is 20% ionised . The freezing point of the solution is: (Given: K_(f)=1.86^(@) C kg" "mol^(-1)" for water")
NARENDRA AWASTHI-DILUTE SOLUTION-Level 3 - Match The Column