The osmotic pressures of 0.010 M solutions of KI and sucrose (`C_(12)H_(22)O_(11)`) are 0.432 atm and 0.24 atm respectively. The van't Hoff factor for KI is :
A
1.8
B
0.8
C
1.2
D
1
Text Solution
Verified by Experts
The correct Answer is:
a
Topper's Solved these Questions
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 1 (Q.62 To Q.91)|1 Videos
The oxidation number of C in sucrose (C_(12)H_(22)O_(11)) is
There is KI and sucrose solution with 0.1 M concentration, if the osmotic pressure of KI and sucorse solution is 0.465 atm and 0.245 atm respectively. Then find the van't Hoff factor of KI and its degree of dissociation.
The osmotic pressure of 0.010 M potassium iodide solution (KI) at 25^(@)C is 0.465 atm . Calculate the van't hoff factor for KI at this concentration. Strategy: Use the modified equation (2.78) to account for the effect of dissociation of KI in water.
The Osmotic pressure of (M)/(10) solution of urea at 27^(0)C is ...... atm
There is AP_(3) and sucrose solution with 0.1 M concentration each . If osmotic pressure of AB_(3) and sucrose solution is 0.72 atm and 0.24 atm respectively at same temperature . The fraction of AB_(3) dissociated will be :
The osmotic pressure of 1 M solution of sucrose is 22.4 atm. What will be the osmotic potential of 0.1 M sucrose solution?
The observed osmotic pressure for a 0.10M solution of Fe(NH_(4))_(2)(SO_(4))_(2) at 25^(@)C is 10.8 atm . The expected and experimental (observed) values of Van't Hoff factor (i) will be respectively: (R = 0.082 L atm k^(-) mol^(-1))
NARENDRA AWASTHI-DILUTE SOLUTION-Level 3 - Match The Column