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At 760 torr pressure and 20^(@)C temprea...

At 760 torr pressure and `20^(@)C` tempreature , 1 L of water dissolves 0.04 gm of pure oxygen or 0.02 gm of pure nitrogen. Assuming that dry air is compound of 20% oxygen and 80% nitrogen (by volume), the masses (in g/L) of oxygen and nitrogen dissolved by 1 L of water at `20^(@)C` exposed to air at a total pressur of 706 torr are respectively :

A

0.008, 0.016

B

0.016, 0.008

C

0.16, 0.08

D

0.04, 0.02

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To solve the problem, we need to determine the masses of oxygen and nitrogen that can be dissolved in 1 L of water at a total pressure of 706 torr, given that at 760 torr, 1 L of water can dissolve 0.04 g of oxygen and 0.02 g of nitrogen. ### Step-by-Step Solution: 1. **Understand the relationship between pressure and solubility**: According to Henry's Law, the solubility of a gas in a liquid is directly proportional to the partial pressure of that gas above the liquid. 2. **Calculate the partial pressures of oxygen and nitrogen in dry air**: - Dry air consists of 20% oxygen and 80% nitrogen by volume. - The partial pressure of oxygen (P_O2) at 706 torr is: \[ P_{O2} = 0.20 \times 706 \text{ torr} = 141.2 \text{ torr} \] - The partial pressure of nitrogen (P_N2) at 706 torr is: \[ P_{N2} = 0.80 \times 706 \text{ torr} = 564.8 \text{ torr} \] 3. **Determine the solubility of oxygen at 706 torr**: - At 760 torr, 1 L of water dissolves 0.04 g of oxygen. - Using Henry's Law, the mass of oxygen dissolved at 706 torr can be calculated as: \[ \text{Mass of } O_2 = \left(\frac{0.04 \text{ g}}{760 \text{ torr}}\right) \times 141.2 \text{ torr} = 0.0074 \text{ g} \] 4. **Determine the solubility of nitrogen at 706 torr**: - At 760 torr, 1 L of water dissolves 0.02 g of nitrogen. - Using Henry's Law, the mass of nitrogen dissolved at 706 torr can be calculated as: \[ \text{Mass of } N_2 = \left(\frac{0.02 \text{ g}}{760 \text{ torr}}\right) \times 564.8 \text{ torr} = 0.0149 \text{ g} \] 5. **Final results**: - The mass of oxygen dissolved in 1 L of water at 706 torr is approximately 0.0074 g. - The mass of nitrogen dissolved in 1 L of water at 706 torr is approximately 0.0149 g. ### Summary of Results: - Mass of oxygen dissolved: **0.0074 g/L** - Mass of nitrogen dissolved: **0.0149 g/L**
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