At 760 torr pressure and `20^(@)C` tempreature , 1 L of water dissolves 0.04 gm of pure oxygen or 0.02 gm of pure nitrogen. Assuming that dry air is compound of 20% oxygen and 80% nitrogen (by volume), the masses (in g/L) of oxygen and nitrogen dissolved by 1 L of water at `20^(@)C` exposed to air at a total pressur of 706 torr are respectively :
A
0.008, 0.016
B
0.016, 0.008
C
0.16, 0.08
D
0.04, 0.02
Text Solution
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The correct Answer is:
To solve the problem, we need to determine the masses of oxygen and nitrogen that can be dissolved in 1 L of water at a total pressure of 706 torr, given that at 760 torr, 1 L of water can dissolve 0.04 g of oxygen and 0.02 g of nitrogen.
### Step-by-Step Solution:
1. **Understand the relationship between pressure and solubility**: According to Henry's Law, the solubility of a gas in a liquid is directly proportional to the partial pressure of that gas above the liquid.
2. **Calculate the partial pressures of oxygen and nitrogen in dry air**:
- Dry air consists of 20% oxygen and 80% nitrogen by volume.
- The partial pressure of oxygen (P_O2) at 706 torr is:
\[
P_{O2} = 0.20 \times 706 \text{ torr} = 141.2 \text{ torr}
\]
- The partial pressure of nitrogen (P_N2) at 706 torr is:
\[
P_{N2} = 0.80 \times 706 \text{ torr} = 564.8 \text{ torr}
\]
3. **Determine the solubility of oxygen at 706 torr**:
- At 760 torr, 1 L of water dissolves 0.04 g of oxygen.
- Using Henry's Law, the mass of oxygen dissolved at 706 torr can be calculated as:
\[
\text{Mass of } O_2 = \left(\frac{0.04 \text{ g}}{760 \text{ torr}}\right) \times 141.2 \text{ torr} = 0.0074 \text{ g}
\]
4. **Determine the solubility of nitrogen at 706 torr**:
- At 760 torr, 1 L of water dissolves 0.02 g of nitrogen.
- Using Henry's Law, the mass of nitrogen dissolved at 706 torr can be calculated as:
\[
\text{Mass of } N_2 = \left(\frac{0.02 \text{ g}}{760 \text{ torr}}\right) \times 564.8 \text{ torr} = 0.0149 \text{ g}
\]
5. **Final results**:
- The mass of oxygen dissolved in 1 L of water at 706 torr is approximately 0.0074 g.
- The mass of nitrogen dissolved in 1 L of water at 706 torr is approximately 0.0149 g.
### Summary of Results:
- Mass of oxygen dissolved: **0.0074 g/L**
- Mass of nitrogen dissolved: **0.0149 g/L**
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