If the boiling point of an aqueous solution containing a non-volatile solute is `100.15^(@)C`. What is its freezing point? Given latent heat of fusion and vapourization of water `80 cal g^(-1)` and `540 cal g^(-1)`, respectively.
A
`0.361^(@)C`
B
`-0.361^(@)C`
C
`-3.61^(@)C`
D
None of these
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The correct Answer is:
b
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DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 1 (Q.62 To Q.91)|1 Videos
If boiling point of an aqueous solution is 100.1^(@)C . What is its freezing point? Given latent heat of fusion and vaporization of water are 80calg^(-1) and 540 calg^(-1) respectively.
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The boiling point of an aqueous solution of a non-volatile solute is 100.15^(@)C . What is the freezing point of an aqueous solution obtained by dilute the above solution with an equal volume of water. The values of K_(b) and K_(f) for water are 0.512 and 1.86^(@)C mol^(-1) :
Calculate the amount of heat required in calorie to change 1 g of ice at -10^(@)C to steam at 120^(@)C . The entire process is carried out at atmospheric pressure. Specific heat of ice and water are 0.5 cal g^(-1) .^(@)C^(-1) and 1.0 cal g^(-1) .^(@)C^(-1) respectively. Latent heat of fusion of ice and vaporization of water are 80 cal g^(-1) and 540 cal g^(-1) respectively. Assume steam to be an ideal gas with its molecules having 6 degrees of freedom. Gas constant R = 2 cal mol^(-1) K^(-1) .
How much heat is required to change 10g ice at 10^(@)C to steam at 100^(@)C ? Latent heat of fusion and vaporisation for H_(2)O are 80 cl g^(-1) and 540 cal g^(-1) , respectively. Specific heat of water is 1cal g^(-1) .
NARENDRA AWASTHI-DILUTE SOLUTION-Level 3 - Match The Column
