Home
Class 11
CHEMISTRY
The vapour pressure of a liqid solution ...

The vapour pressure of a liqid solution containing A and B is 99 torr. Colvulate mole % of in vapour phese.
(Given : `P_(A^(@)) = 100 torr , P_(B^(@)) =80 torr)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of calculating the mole percentage of component B in the vapor phase of a liquid solution containing A and B, we will follow these steps: ### Step 1: Understand the Given Data We have the following information: - Total vapor pressure of the solution, \( P_{total} = 99 \, \text{torr} \) - Vapor pressure of pure A, \( P_{A}^{0} = 100 \, \text{torr} \) - Vapor pressure of pure B, \( P_{B}^{0} = 80 \, \text{torr} \) ### Step 2: Use Raoult's Law According to Raoult's Law, the total vapor pressure of a solution can be expressed as: \[ P_{total} = P_{A}^{0} \cdot x_A + P_{B}^{0} \cdot x_B \] where \( x_A \) and \( x_B \) are the mole fractions of A and B in the liquid phase, respectively. Since \( x_A + x_B = 1 \), we can express \( x_A \) as \( 1 - x_B \). ### Step 3: Substitute into the Equation Substituting \( x_A \) into the equation gives: \[ P_{total} = P_{A}^{0} \cdot (1 - x_B) + P_{B}^{0} \cdot x_B \] Substituting the known values: \[ 99 = 100 \cdot (1 - x_B) + 80 \cdot x_B \] ### Step 4: Simplify the Equation Expanding the equation: \[ 99 = 100 - 100x_B + 80x_B \] Combining like terms: \[ 99 = 100 - 20x_B \] ### Step 5: Solve for \( x_B \) Rearranging the equation: \[ 20x_B = 100 - 99 \] \[ 20x_B = 1 \] \[ x_B = \frac{1}{20} \] ### Step 6: Calculate Mole Fraction of B in the Vapor Phase The mole fraction of B in the vapor phase, \( y_B \), can be calculated using: \[ y_B = \frac{x_B \cdot P_{B}^{0}}{P_{total}} \] Substituting the values: \[ y_B = \frac{\left(\frac{1}{20}\right) \cdot 80}{99} \] Calculating: \[ y_B = \frac{4}{99} \] ### Step 7: Convert Mole Fraction to Mole Percentage To find the mole percentage of B in the vapor phase, we multiply by 100: \[ \text{Mole percentage of B} = y_B \cdot 100 = \frac{4}{99} \cdot 100 \approx 4.04\% \] ### Final Answer The mole percentage of B in the vapor phase is approximately **4%**. ---
Promotional Banner

Topper's Solved these Questions

  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 1 (Q.62 To Q.91)|1 Videos
  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 2|3 Videos
  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos
  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

Similar Questions

Explore conceptually related problems

2 moles each of liquids A and B are dissolved to form an ideal solution. What will be the mole fraction of B in the vapour phases ? p_(A)^(@) = 120 " torr ", p_(B)^(@) = 80 torr

Two liquid A & B form an ideal solution. What is the vapour pressure of solution containing 2 moles of A and 3 moles at B at 300K? [Given: At 300K, Vapour pr. Of pure liquid A ("P"_("A")^(@)) =100 torr, Vapour pr. Of pure liquid B ("P"_("B")^(@)) = 300 torr]

At 300K, the vapour pressure of an ideal solution containing 3 mole of A and 2 mole of B is 600 torr. At the same temperature, if 1.5 mole of A & 0.5 mole of C (non-volatile) are added to this solution the vapour pressure of solution increased by 30 torr. What is the value of "P"_("B')^(@) ?

The vapour pressure of pure liquid 'A" at 310^(@)"c" is 120 torr. The vapour pressure of this liquid in solution with liquid B is 72 torre. Calculate the mole of fraction of 'A' in solution if the mixture obeys Raoult's law.

At 25^(@)C , the total pressure of an ideal solution obtained by mixing 3 mole of A and 2 mole of B, is 184 torr. What is the vapour pressure (in torr) of pure B at the same temperature (Vapour pressure of pure A at 25^(@)C is 200 torr) ?

20 moles of liquid A are mixed with 20 moles of liquid B to form an ideal binary solution. Calculate moles of A in liquid state when half of the solution has vaporized : ( Given : P_(A)^(@)=100 " torr", P_(B)^(@)=121 " torr" )

The vapour pressure of solvent is 20 torr, while that of its dilute solution is 17 torr , the mole-fraction of the solvent is

At 298K , the vapour pressure of pure liquid n-butane is 1823 torr and vapour pressure of pure n-pentane is 521 torr and form nearly an ideal solution. a. Find the total vapour pressure at 298 K of a liquid solution containing 10% n-butane and 90% n-pentane by weight, b. Find the mole fraction of n-butane in solution exerting a total vapour pressure of 760 torr. c. What is composition of vapours of two components (mole fraction in vapour state)?