Calculate elevation in boiling point for 2 molal aqueous solution of glucose (Given: K_(b(H_2O) =0.5K kg mol^(-1)))
Calculate depression of freezing point for 0.56 molal aq. Solution of KCl. (Given : K_f(H_(2)O) = 1.8 kg mol^(-1) ).
What is the boiling point of 1 molal aqueous solution of NaCl (K_b)=0.52 K molal^-1]
The depression of freezing point of a solvent (b.p:303 K) for a particular solution is 0.153 K. Calculate the molal elevation constant if the boiling point of the solution is 304.52 K .(K_(f) =1.68 K kg mol ^(-1))
Elevation of boiling point of 1 molar aqueous glucose solution ("density"=1.2g//ml) is
Elevation in boiling point of an aqueous solution of urea is 0.52 ( k_(b) "for water"=0.52K"molality"^(-1)) . The mole fraction is urea in this solution is :
0.1 molal aqueous solution of an electrolyte AB_(3) is 90% ionised. The boiling point of the solution at 1 atm is ( K_(b(H_(2)O)) = 0.52 kg " mol"^(-1) )
A solution of 2.8g of Cdl_(2) molar mass =364g "mol"^(-1) ) in 20g water has elevation in boiling point of 0.20^(0) . What is molecular state of Cdl_(2) in aqueous solution ? [K_(b)(H_(2)O)=0.52^(0) "mol"^(-1)kg]
NARENDRA AWASTHI-DILUTE SOLUTION-Level 3 - Match The Column
